25=(1/5)^x

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Solution for 25=(1/5)^x equation: 



25=(1/5)^x

We move all terms to the left:

25-((1/5)^x)=0



Domain of the equation: 5)^x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+1/5)^x)+25=0

We multiply all the terms by the denominator


-((+1+25*5)^x)=0



We calculate terms in parentheses: -((+1+25*5)^x), so:

(+1+25*5)^x

We add all the numbers together, and all the variables

126^x

Back to the equation:

-(126^x)



x=0/1

x=0

Równanie nie ma rozwiązania

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